mini disk
A triangle with sides of 4.76 inches or less.
Yes because the diameter of the circle is less than the sides of the square.
Two locations less than 0.01 inches apart could not be marked separately
Use the fact that the diameter is twice the radius. d = r - 4; replacing for d, 2r = r - 4
50 sq. in. I am very certain.... * * * * * You may be certain but you are wrong! A pipe, with a diameter of 5 inches has an area of 19.63 square inches - substantially less than 50.
A diskette, or "floppy disk", is a small, removable magnetic disk. The earliest models had a diameter of 8 inches and a capacity of less than 200 kilobytes. The diskette is still in use today, using a physical format pioneered by Apple, with a standard capacity of 1.44 megabytes. A CD, or "compact disc", is a small, removable optical disc, with a capacity of around 800 megabytes. Originally they were a write-once technology, but rewriteable discs are now available.
A triangle with sides of 4.76 inches or less.
The circumference of a Major League base can vary; not less than 9 inches or more than 9.25 inches. That would make the diameter of the ball vary between 2.87 inches and 2.94 inches.
The circumference of any circle with a diameter of 12 inches is 12 (pi) = 37.7 inches (rounded) That's 4.72% more than 1 yard.
The diameter of the golf ball must be at least 1.680 inches or 42.67 millimeters
Yes because the diameter of the circle is less than the sides of the square.
Two locations less than 0.01 inches apart could not be marked separately
Use the fact that the diameter is twice the radius. d = r - 4; replacing for d, 2r = r - 4
50 sq. in. I am very certain.... * * * * * You may be certain but you are wrong! A pipe, with a diameter of 5 inches has an area of 19.63 square inches - substantially less than 50.
Multiply the diameter by the value of Pi, then multiply by the height and you'll have your answer. Hint: It's more than 37, but less than 38 !
It is not necessary that a thinner convex lens have less optical power or a thicker lens has more optical power
To determine how many half-inch diameter spheres fit into a cylinder that is 18 inches tall with a diameter of 5 inches, we first calculate the volume of the cylinder and the volume of one sphere. The radius of the cylinder is 2.5 inches, so its volume is approximately 18 × π × (2.5)² ≈ 141.37 cubic inches. The radius of the half-inch diameter sphere is 0.25 inches, so its volume is about (4/3)π(0.25)³ ≈ 0.0654 cubic inches. Dividing the cylinder's volume by the sphere's volume gives approximately 2165 spheres that can fit into the cylinder, assuming no gaps between them. However, the actual number may be less due to packing efficiency.