To find the ordered pairs in any equation, just plug in any number for x and solve for y.
If your equation is meant to be y=1+5x, then if x=0 then y=1+5*0, y=1 so the first ordered pair would be (0,1)
If your equation is meant to be y=(1/5)x, then if x=0 then y=(1/5)*0, y=0, so the first ordered pair would be (0,0)
3x
(1, 0.2), (2, 0.1)
The question does not contain an equation nor an inequality. There cannot, therefore be any ordered pairs which can satisfy an expression.
It is the set of infinitely many ordered pairs, (x, y) such that the two satisfy the given equation.
Any pair of numbers at all, as long as one of them is triple the other one.
3x
I am sorry but the question is incomplete. You have not mentioned the ordered pairs and the equation is incomplete as well.
There are infinitely many ordered pairs. One of these is (0, 0).
There are an infinite number of ordered pairs that satisfy the equation.
1,6 2,12 3,18 4,24 5,30
7
(1, 0.2), (2, 0.1)
The question does not contain an equation nor an inequality. There cannot, therefore be any ordered pairs which can satisfy an expression.
It is the set of infinitely many ordered pairs, (x, y) such that the two satisfy the given equation.
Any pair of numbers at all, as long as one of them is triple the other one.
The question cannot be answered unless a specific equation is cited.
it is 7yx978