0.5*(172-51) = 119 diagonals
There is no such polygon that has 95 diagonals because a 15 sided polygon has 90 diagonals and a 16 sided polygon has 104 diagonals.
To find the number of diagonals in a polygon with ( n ) sides, you can use the formula ( \frac{n(n-3)}{2} ). For a 17-gon, substituting ( n = 17 ) gives: [ \frac{17(17-3)}{2} = \frac{17 \times 14}{2} = \frac{238}{2} = 119. ] Thus, a 17-gon has 119 diagonals.
That polygon is called a "triangle". It has no diagonals.
There are 119 diagonals.
A lot. :)Improved Answer:-119
0.5*(172-51) = 119 diagonals
There is no such polygon that has 95 diagonals because a 15 sided polygon has 90 diagonals and a 16 sided polygon has 104 diagonals.
To find the number of diagonals in a polygon with ( n ) sides, you can use the formula ( \frac{n(n-3)}{2} ). For a 17-gon, substituting ( n = 17 ) gives: [ \frac{17(17-3)}{2} = \frac{17 \times 14}{2} = \frac{238}{2} = 119. ] Thus, a 17-gon has 119 diagonals.
A polygon that has 104 diagonals will have 16 sides
That polygon is called a "triangle". It has no diagonals.
There are 119 diagonals.
An 11 sided polygon has 44 diagonals.
There are 90 diagonals in a 15-sided polygon.
A four-sided polygon has two diagonals.
No
a convex polygon