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A polygon with an interior angle sum of 2880 degrees has 20 sides. This can be calculated using the formula for the sum of interior angles, which is ( (n - 2) \times 180 ) degrees, where ( n ) is the number of sides. Setting the equation ( (n - 2) \times 180 = 2880 ) and solving for ( n ) gives ( n = 20 ). Therefore, the polygon is a 20-sided figure, known as an icosagon.

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How many sides does a 2880 polygon have?

A polygon whose interior angles are 2880 degrees has 18 sides.


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2880 degrees


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18 Angles on a straight line = 180 degrees interior angles 2880 + exterior angles 360 = 3240 degrees 3240 divided by 180 = 18 sides Note that the exterior sum of angles of any polygon is always 360 degrees.


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(18-2)*180 = 2880 degrees


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Interior angle of 18 sided shape?

The interior angles of an 18 sided polygon add up to 2880 degrees


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How do you find the measure of each interior angle of a regular polygon that has 135 diagonals?

First find the number of sides of the polygon and let it be x: Rearrange the diagonal formula: 0.5*(x2-3x) = 135 into a quadratic equation Which is: x2-3x-270 = 0 and solving the equation gives x positive value of 18 Therefore the polygon has 18 sides Sum of interior angles: (18-2)*180 = 2880 degrees Each interior angle: 2880/18 = 160 degrees