The weight of the box is irrelevant. The only thing that matters is how hard you push on it.
Since it's the only number given, let's assume that the 10 Newtons is the force you applied to the box,
and that by applying that force to the box, you were able to move it 5 meters in 2 seconds.
The work you did is [ force x distance ] = 10 x 5 = 50 joules.
The power is [ energy / time ] = 50/2 = 25 joules per second = 25 watts.
.47 watt
80 J
The person's speed is 2 meters per second. The power required for him to accomplish that depends on his weight, on his efficiency of movement, on whether he's moving horizontally or vertically, etc., all of which the question neglects to specify.
320 meters
1200j
.47 watt
two watts a second
The work required to move the truck is 600 N (600 kg-m/sec2) times 30 meters = 18000 joules. If this is done in 15 seconds, the average power was 1200 watts (kg-m2/sec3).
The power required to move the chair can be calculated using the formula Power = force x distance รท time. Plugging in the values: P = 51 N x 5 m รท 15 s = 17 Watts. Therefore, it would take approximately 17 Watts of power to move the chair 5 meters in 15 seconds using a force of 51 Newtons.
The object will move a total distance of 80 meters, which is calculated by multiplying the speed (10 m/s) by the time (8 seconds).
80 J
A force of 100 newtons acting through a distance of 10 metersresults in 1,000 joules of energy transferred.If it all takes place in 10 seconds then the average rate of energytransfer (power) during that interval is(1,000/10) = 100 joules per second = 100 watts.
Power is equal to work done divided by time, where work done is force multiplied by distance. In this case, the work done is 100 newtons * 10 meters = 1000 joules. Therefore, the power used would be 1000 joules / 5 seconds = 200 watts.
The person's speed is 2 meters per second. The power required for him to accomplish that depends on his weight, on his efficiency of movement, on whether he's moving horizontally or vertically, etc., all of which the question neglects to specify.
320 meters
1200j
Your power output would be 100 Watts. This can be calculated by dividing the work done (force x distance) by the time taken to do the work (10 seconds).