Q: What prime numbers less than 60 are divided by 7 and give the remainder 3?

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49 can be divided by these numbers without leaving a remainder: 1 7 and 49.

No. It is an even number, because it is divisible by 2. "Odd" numbers give you a non-zero remainder after you divide by 2. "Even" numbers give you a remainder of 0, after you divide by 2. 332 divided by 2 is 166 with a remainder of 0, so it is "even". But 333 divided by two is 166 with a remainder of 1, so it is "odd".

3

61

23457 divided by 23456 leaves a remainder of 1, and it is divisible by 7. So that is one of infinitely many possible answers.

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49 can be divided by these numbers without leaving a remainder: 1 7 and 49.

546

First, the word is remainder, not reminder.In any case, none of the followed numbers would give a remainder of 2 since there are no such numbers!First, the word is remainder, not reminder.In any case, none of the followed numbers would give a remainder of 2 since there are no such numbers!First, the word is remainder, not reminder.In any case, none of the followed numbers would give a remainder of 2 since there are no such numbers!First, the word is remainder, not reminder.In any case, none of the followed numbers would give a remainder of 2 since there are no such numbers!

2, 5, 7, 19 and 31

No. It is an even number, because it is divisible by 2. "Odd" numbers give you a non-zero remainder after you divide by 2. "Even" numbers give you a remainder of 0, after you divide by 2. 332 divided by 2 is 166 with a remainder of 0, so it is "even". But 333 divided by two is 166 with a remainder of 1, so it is "odd".

Any number can be divided by 36 but most will give a remainder. To find all the numbers which when divided by 36 do not give a remiander use the formula 36n where n is any positive integer.

3

Here are the prime numbers between 10 and 30: 11, 13, 17, 19, 23, 29 Prime numbers are those numbers which cannot be divided to give an integer result except when divided by themselves or by 1.

The remainder is the number that is left over after the initial value has been divided as much as it can. If any numbers greater than 48 were present as a remainder, then these could be divided further into 48. If 48 is present as the remainder, then this can be divided by 48 to give 1, leaving no remainder. Thus, the largest possible remainder if the divisor is 48 is 47.

1035 divided by 88 is 11 with remainder 67

61

23457 divided by 23456 leaves a remainder of 1, and it is divisible by 7. So that is one of infinitely many possible answers.