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What quantity of a 80 percent acid solution must be mixed with a 30 percent solution to produce 300 mL of a 40 percent solution?

Anonymous

∙ 13y ago

Updated: 10/18/2022

Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300.

Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300]

80Q + 9000 - 30Q = 12000

50Q = 3000

Q = 60...........which means (300 - Q) = 240

60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.

Wiki User

∙ 13y ago

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