Wiki User
∙ 12y agoLet Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300.
Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300]
80Q + 9000 - 30Q = 12000
50Q = 3000
Q = 60...........which means (300 - Q) = 240
60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.
Wiki User
∙ 12y ago10
210Type your answer here...
25 gallons
120liters
1.5 pints
133.33
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
mary mixed 2l of an 80% acid solution with 6l of a 20% acid solution. what was the percent of acid in the resulting mixture
10
210Type your answer here...
25 gallons
120liters
1.5 pints
120
4 ounces
When iodine solution is mixed with starch solution they produce blue-black color.
Answer:12mL of 50% solution and 24mL of 20% solution must be mixed to produce 36mL of a 30% acid solutionLet x = 50% acid solutiony = 20% acid solution Equations:x + y = 36mL ----equation (1)0.5x + 0.2y = 0.3 * 360.5x + 0.2y = 10.8multiplying by 105x + 2y = 108 ----equation (2)eliminating equations (1) and (2)-2(x + y = 36)-2-2x -2y = -725x +2y = 108=========3x = 36x=12substitute x=12 to equation (1)12 + y = 36y = 36 - 12y = 24thus 12mL of 50% solution and 24mL of 20% solution must be mixed to produce 36mL of a 30% acid solution