That depends on what the vector, itself, represents. For example, if the vector represents velocity, then the magnitude of the vector represents speed. If the vector represents displacement, then the magnitude of the vector represents distance.
Blue represents trustworthy
M represents 1000, C represents 100, x represents 10. 2220 as Roman numerals is MMCCXX.
To write 1 6 1983 in Roman numerals, you would write it as VI.X.MCMLXXXIII. VI represents 6, X represents 10, MC represents 1100, M represents 1000, LXXX represents 80, and III represents 3.
The Roman numeral MMXX represents the number 2020. In Roman numerals, M represents 1000 and X represents 10. So, MM represents 2000 and XX represents 20. When we add them together, we get 2020.
A zigzag line represents the molecule with the formula C6H14, which is hexane. Each angle in the zigzag line represents a carbon atom, and the hydrogen atoms are implied to be attached to the carbons.
The molecular formula for C3H7 is C3H7. This formula represents a hydrocarbon with 3 carbon atoms and 7 hydrogen atoms in its structure.
C6H14 is an alkane. Alkanes have the general formula CnH2n+2, where n represents the number of carbon atoms and only single bonds are present between carbon atoms. CH2O does not fit this general formula for alkanes as it contains oxygen and is not a hydrocarbon. C3H4 is also not an alkane as it does not have the general formula CnH2n+2.
Yes, it does C6H14 is the saturated form called hexane.
no
There are five compounds with the chemical formula C6H14. They are hexane, 2-methylpentane, 3-methylpentane, 2,2-dimethylbutane, and 2,3-dimethylbutane.
The balanced equation is: C6H14 + 9O2 -> 7H2O + 6CO2
C6h14
YES
Because alkanes follow the formula CnH2n+2 as 6*2+2=14, we can conclude c6h14 is an alkane
The different elements of C6H14 are carbon and hydrogen. If by different elements you mean isomers then they would be:Hexane2-methylpentane3-methylpentane2,2-dimethylbutane2,3-dimethylbutane
The molecular formula of all the hexanes is C6H14. (Remember the numbers should be subscripts.) However there are isomers: CH3CH2CH2CH2CH2CH3, (CH 3 ) 2 CH(CH 2 ) 2 CH 3 CH 3 CH 2 CH(CH 3 )CH 2 CH 3 CH 3 CH(CH 3 )CH(CH 3 )CH 3 CH 3 C(CH 3 ) 2 CH 2 CH 3 Wikipedia shows them clearly.