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Given 2sin s equals cos s find all possible values of sin s?
2sin s = cos s; whence, 4sin2 s = cos2 s = 1 - sin2s, and 5sin2 s = 1. Therefore sin s = ±√0.2 = 0.4472, approx. Check: cos2 s = 1 - 0.2 = 0.8, whence, cos s = ±√0.8 = ±2√0.2 = 2 sin s.
What is the integral of 1 divided by cos x multiplied by sin cubed x?
Given the limitations of this browser, I will use S to denote integral (the stretched S).Int = S cos(x)*sin3(x) dxLet t = sin(x) then dt = cos(x)dxso Int = S t3dt = 1/4*t4 + cSubstituting back for x,Int = sin4(x) / 4 + cGiven the limitations of this browser, I will use S to denote integral (the stretched S).Int = S cos(x)*sin3(x) dxLet t = sin(x) then dt = cos(x)dxso Int = S t3dt = 1/4*t4 + cSubstituting back for x,Int = sin4(x) / 4 + cGiven the limitations of this browser, I will use S to denote integral (the stretched S).Int = S cos(x)*sin3(x) dxLet t = sin(x) then dt = cos(x)dxso Int = S t3dt = 1/4*t4 + cSubstituting back for x,Int = sin4(x) / 4 + cGiven the limitations of this browser, I will use S to denote integral (the stretched S).Int = S cos(x)*sin3(x) dxLet t = sin(x) then dt = cos(x)dxso Int = S t3dt = 1/4*t4 + cSubstituting back for x,Int = sin4(x) / 4 + c
What is the speed of a 2x 4x or 8x AGP card?
The speed of an AGP (Accelerated Graphics Port) card varies based on its version: 2x, 4x, or 8x. The "x" indicates the multiplier of the base speed of 66 MHz; therefore, a 2x AGP runs at 266 MB/s, a 4x AGP at 533 MB/s, and an 8x AGP at 1066 MB/s. These speeds represent the maximum data transfer rates between the graphics card and the motherboard. The higher the AGP version, the greater the bandwidth available for graphics data.
How do you find the area of a cone with only the angle degree and base radius given?
Area of the cone part is pi*r*s (s is the slant height which is the hypotenuse of the triangle formed by the radius and the altitude). cosine(theta) = r/s, so s = r/cos(theta), and A = pi*r*s = pi*r^2 / cos(theta). The area of the circle part is given by pi*r^2. Then just add them together.
Solve sec2x equals secx plus 2?
You must mean, either,(1) sec2 x = sec x + 2, or(2) sec(2x) = sec x + 2.Let's first assume that you mean:sec2 x = sec x + 2;whence,if we let s = sec x, we have,s2 = s + 2,s2 - s - 2 = (s - 2)(s + 1) = 0, ands = 2 or -1; that is,sec x = 2 or -1.As, by definition,cos x = 1/sec x ,this means thatcos x = ½ or -1.Therefore, providing that the first assumption is correct,x = 60°, 180°, or 300°; or,if you prefer,x = ⅓ π, π, or 1⅔ π.Now, let's assume, instead, that you mean:sec(2x) = sec x + 2;whence,1/(cos(2x) = (1/cos x) + 2.If we let c = cos x,then we have the standard identity,2c2 - 1 = cos (2x); and,thus, it follows that1/(cos(2x) = 1/(2c2 - 1)= (1/c) + 2 = (1 + 2c)/c.This gives,1/(2c2 - 1) = (1 + 2c)/c;(2c2 - 1)(2c + 1) = 4c3 + 2c2 - 2c - 1 = c; and4c3 + 2c2 - 3c - 1 = (c + 1)(4c2 - 2c - 1) = 0.As our concern is only with real roots,c = cos x = -1; and,therefore, providing that the second assumption is correct,x = 180°; or,if you like,x = π.
What is cos 295?
Cos 295 fall s in the 4th quadrant where cosine is positive cos 295 = cos (360-295) = cos 65 = 0.4226
An object is undergoing simple harmonic motion with period 1.210 s and amplitude 0.610 m. At t equals 0 the object is at x equals 0. How far is the object from the equilibrium position at time 0.485 s?
I got -0.495 m. I can't promise you this is correct, but here's my method:the position as a function of time is x(t)=A*cos(sqrt(k/m)*t)you already have A and t values, and you can solve for sqrt(k/m) by using the period they gave you.....T=2pi/(sqrt(k/m))sqrt(k/m)=2pi/TPlug and chug. Bada bing.
Given 2sin s equals cos s find all possible values of sin s?
2sin s = cos s; whence, 4sin2 s = cos2 s = 1 - sin2s, and 5sin2 s = 1. Therefore sin s = ±√0.2 = 0.4472, approx. Check: cos2 s = 1 - 0.2 = 0.8, whence, cos s = ±√0.8 = ±2√0.2 = 2 sin s.
Do P-waves have a higher amplitude than S-waves?
S-waves actually have a higher amplitude, despite being slower than P-waves. It is this amplitude that indicates stress, which is why S-waves can't travel through liquids, as liquids cannot support the stresses of S-waves
A bob of mass 50 g oscillates as a simple pendulum with an amplitude 5 cm and period 2 s Calculate the instantaneous velocity of the bob and the tension in the supporting thread?
10000000000000000000000000000000000000to33333333333333333333333333333333333333330000000000000000000000000000000
What is the data connection speed of AGP 8x?
Max data rate of 2133MB/s
Find the perimeter of the cord ra1 cos?
r=a(1+cos x) r^2=a^2(1+cos x)^2 = a^2 + 2[a^2][cos(x)] + [a^2][cos^2(x)] dr/dx = r' = -a sin(x) (r')^2 = [a^2][sin^2 (x)] Therefore perimeter (s) of curve r=a(1+cos x) in polar coordinate with x vary from 0 to Pi (due to curve is symmetry on axis x=0) is s = 2 Int { sqrt[r^2 + (r')^2] } dx where x vary from 0 to Pi. Thus sqrt[r^2 + (r')^2] = sqrt { a^2 + 2[a^2][cos(x)] + [a^2][cos^2 (x)] + [a^2][sin^2 (x)] } = sqrt { (2a^2)[1+cos(x)] } = [sqrt(2)]a {sqrt [1+cos(x)]} Then s = 2[sqrt(2)]a . Int {sqrt [1+cos(x)]} dx Let 1+cos(x) = 1+2cos^2 (x/2) - 1 = 2cos^2 (x/2) s = 2[sqrt(2)]a . Int {sqrt [2cos^2 (x/2)]} dx s = 4a . Int [cos(x/2)] dx where x vary from 0 to Pi s = 4a [sin(x/2)]/(1/2) s = 8a [sin(Pi/2) - sin(0)] s = 8a
What is the integral of 1 divided by cos x multiplied by sin cubed x?
Given the limitations of this browser, I will use S to denote integral (the stretched S).Int = S cos(x)*sin3(x) dxLet t = sin(x) then dt = cos(x)dxso Int = S t3dt = 1/4*t4 + cSubstituting back for x,Int = sin4(x) / 4 + cGiven the limitations of this browser, I will use S to denote integral (the stretched S).Int = S cos(x)*sin3(x) dxLet t = sin(x) then dt = cos(x)dxso Int = S t3dt = 1/4*t4 + cSubstituting back for x,Int = sin4(x) / 4 + cGiven the limitations of this browser, I will use S to denote integral (the stretched S).Int = S cos(x)*sin3(x) dxLet t = sin(x) then dt = cos(x)dxso Int = S t3dt = 1/4*t4 + cSubstituting back for x,Int = sin4(x) / 4 + cGiven the limitations of this browser, I will use S to denote integral (the stretched S).Int = S cos(x)*sin3(x) dxLet t = sin(x) then dt = cos(x)dxso Int = S t3dt = 1/4*t4 + cSubstituting back for x,Int = sin4(x) / 4 + c
Why is megaman blue?
Cos he`s into the music genre!!! I dont realy know, probably cos some game designer liked blue?
What happens to the amplitude when the amount of energy in s wave increases?
When the amount of energy in an S wave increases, the amplitude of the wave also increases. This means that the S wave will have a greater maximum displacement from its resting position as it carries more energy.
Why do arrows in a food chain point towards the consumer?
cos that s life
Why couldn't black people vote during the 1930's?
cos of segregation
