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To find the measure of each interior angle of a regular pentagon, first calculate the sum of the interior angles using the formula ( S = 180(n-2) ). For a pentagon, ( n = 5 ), so ( S = 180(5-2) = 180 \times 3 = 540 ) degrees. Since a regular pentagon has equal interior angles, divide the sum by the number of angles: ( \frac{540}{5} = 108 ) degrees. Therefore, each interior angle of a regular pentagon measures 108 degrees.

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1d ago

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What is the measure of the interior angle of a regular pentagon?

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What is the measure of each interior angle of a pentagon?

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What is the measure of each interior angle of a regular pentagon?

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What is the measure of an interior angle of a regular pentagon rounded to the nearest tenth?

To the nearest tenth, the interior angle of a regular pentagon is 108.0o In a regular pentagon, the sum of the interior angles is (5 - 2) x 1800 = 3 x 1800 = 540o In a regular pentagon, the interior angles are all the same size and are 5400 ÷ 5 = 108o which to the nearest tenth is 108.0o


What would the measure of one interior angle of a regular pentagon be?

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The measure of an interior angle of a regular pentagon can be calculated using the formula ((n - 2) \times 180^\circ / n), where (n) is the number of sides. For a pentagon, (n = 5), so the interior angle measures ((5 - 2) \times 180^\circ / 5 = 108^\circ). Therefore, each interior angle of a regular pentagon measures 108 degrees.