Q: What set of numbers does the number 86 belong to?

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One reason the number 89 does not belong is because it is a prime number and the other numbers are not.

8 numbers, so the median is the mean average of the 4th and 5th numbers. 4th number is 86 5th number is 86 median = (86 + 86) ÷ 2 = 86.

It is 2 because the prime numbers of 86 are 2 and 43

86 = 2 x 43

86 is an integer and there s no sensible representation of integers as mixed numbers.

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One reason the number 89 does not belong is because it is a prime number and the other numbers are not.

They are members of the infinite set of numbers of the form 86*k where k is an integer. Since the set is infinite, it is not possible to list them.

8 numbers, so the median is the mean average of the 4th and 5th numbers. 4th number is 86 5th number is 86 median = (86 + 86) ÷ 2 = 86.

They are members of the infinite set of numbers of the form 86*k where k is an integer. Since the set is infinite, it is not possible to list them.

If two consecutive numbers add up to 86 then we can set up an equation like this: x=the first number So it makes sense that x+2=the second number (since the numbers are consecutive) And you know the sum of the two is 86. So the resulting equation is (x) + (x+2) = 86 => 2x + 2 = 86 2x = 84 x = 42 So the two numbers are 42 and 44.

They are all part of a larger set of numbers defined by the pattern of adding nine to the previous number in ascending order.

It is 2 because the prime numbers of 86 are 2 and 43

86 = 2 x 43

86 is an integer and there s no sensible representation of integers as mixed numbers.

The third number is 112, the numbers are 86, 86, 112, 172

Factors of 27: 1, 3, 9, 27 Factors of 86: 1, 2, 43, 86 GCF (27, 86) = 1

The set is bimodal: its modes are 84 and 86 which appear twice. All the other numbers appear at most once.