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x = 59
You can multiply:1 x 62 x 33 x 26 x 1
26 x 33 = 1728
Order the numbers by size. Then the median of three numbers must be the middle number. So the second number is 7. The mean is 11 so their sum is 3*11 = 33 so the sum of the first and third is 33-7 = 26. The range is 14 so if one of the numbers is x, another must be x+14. Now x must be the smallest or the second (=7) [It can't be the largest because x+14 is bigger] If x = 7 then x+14 = 21 and the first must be 26-21 = 5 but then the range becomes 16. So x is not 7. So x is the smallest number, and x+x+14 = 26 ie 2x+14=26 or 2x = 12 or x = 6 Then the third number is x+14 = 20 So the three are 6,7 and 20.
abs(x-33) or |x-33|