56/7 = 8
(24*76)+(76*56) = 5600
If: 14x = 56Then x = 56/14Therefore: x = 4
You can use four 7s to make 56 by applying mathematical operations. One way to achieve this is: ( (7 \times 7) + (7 \div 7) = 49 + 1 = 50 ), which does not directly work. Instead, you can also express it as ( 7 \times (7 + 7) \div 7 = 56 ). However, a correct and straightforward solution is simply ( 7 \times 8 = 56 ).
the answer would be 5 over six * * * * * No it would not! It would be 56/10 which simplifies to 28/5.
It would be 56
49
The solution to 12 plus 56 plus 6 is 74. The solution to 12 times 56 times 6 is 4,032.
The freezing point of a 56% acetic acid solution would be lower than that of pure acetic acid (16.6°C). The exact freezing point would depend on the specific properties of the solution and would require a calculation based on its colligative properties.
(24*76)+(76*56) = 5600
If: 14x = 56Then x = 56/14Therefore: x = 4
To prepare a 2 M solution of KOH, you would need to calculate the moles of KOH required first. Then use the formula mass of KOH (56 g/mol) to convert moles to grams. First, calculate the moles needed: 2 moles/L * 0.25 L = 0.5 moles. Then, convert moles to grams: 0.5 moles * 56 g/mole = 28 grams of KOH needed.
You can use four 7s to make 56 by applying mathematical operations. One way to achieve this is: ( (7 \times 7) + (7 \div 7) = 49 + 1 = 50 ), which does not directly work. Instead, you can also express it as ( 7 \times (7 + 7) \div 7 = 56 ). However, a correct and straightforward solution is simply ( 7 \times 8 = 56 ).
y / 8 = 56 So multiply both sides by 8 to get y = 56 * 8 So y = 448
56% Since it is already out of 100, its just the number sold. In this case, 56. Had it been out of some other number, we would have had to use math to find the answer.
the answer would be 5 over six * * * * * No it would not! It would be 56/10 which simplifies to 28/5.
56
It would be 56