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Mass of the boxcar = M = 200 (1000 kg ) = 2*105 kg

inclination = θ= 2.5o

acceleration = a= g sin θ = (9.8) sin 2.5o = 0.427 m/s2

during the time = t = 10 sec

initial velocity = U = 0 m/s

final velocity = V = ?

a = V - U / t

V = at = (0.427)(10) = 4.27 m/s

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Q: What speed does a boxcar have after 10 seconds if the boxcar mass of 200 tons at rest becomes uncoupled on a 2.5 grade and the track is considered frictionless?
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