you add 1+1= 25 simple ;)
Cost = Fixed + (variable x units)
The equation x=c where c is a constant is the equation of a vertical line. It can't be a function but it is linear so the answer is no. For example, the vertical line produced by the linear equation x = 3 does not represent a function. We cannot write this equation so that y is a function of x because the only x-value is 3 and this "maps" to every real-number y.
you simply differentiate the function and integrate the reamaing trigonometric equation leavin surd form in you ranswer
10y = x ======
it depends, what form is the equation written in? write it with variables though, instead of constants, and I'll try to get back to ya
MATH 1003?
The normal way of showing that y is a function of x is to write y = f(x).
y=(4+8)2
Read the problem. Write each fact as a variable expression. Write each fact as a sentence.
you have to solve y to get the answer
you add 1+1= 25 simple ;)
Cost = Fixed + (variable x units)
let's take an arbitrary equation, or maybe two or three so you can see how to do it. y=2x+6 t=z^2+3z w=r^4+pi Ok, the first equation, you pick the x and put it in the equation and multiply it by 2 then add 6. If you do all this you get y. So y is really a function of x or function of x is written f(x) is the way we say this So to write the equation in function notation we write f(x)=2x+6 Same thing for the second equation z is what we put in. It is the independent variable. So t is just a function of z we write f(z)=z^2+3z Last equation is the same f(r)=r^4+pi
Y = X2 ===== This is a parabolic function because it passes the vertical line test. ( you should know what that test is )
slope 5/6 through (-18,6)
Well, it would be hard to write an inverse function of -4, since -4 is not a function in the first place.