Real numbers, Rational numbers, and Integers.
The other three are Irrational (numbers that cannot be expressed as fractions), Whole numbers (0,1,2,3,4...) and Natural numbers (1,2,3,4,5...).
EDIT: There is also imaginary numbers (√-1, often expressed as i ) and complex numbers (numbers that contain both a real and imaginary part i.e. a+bi where a and b are real numbers and i is an imaginary number)
Note that an empty set is included for the set of 11 numbers. That is 1 subset. Since order doesn't matter for this type of situation, we count the following number of subsets. 1-item subset: 11 choose 1 2-item subset: 11 choose 2 3-item subset: 11 choose 3 4-item subset: 11 choose 4 5-item subset: 11 choose 5 6-item subset: 11 choose 6 7-item subset: 11 choose 7 8-item subset: 11 choose 8 9-item subset: 11 choose 9 10-item subset: 11 choose 10 11-item subset: 11 choose 11 Note that the pattern of these values follows the Fibonacci sequence. If we add all of these values and 1 altogether, then you should get 2048 subsets that belong to the given set {1,2,3,4,5,6,7,8,9,10,11}. Instead of working out with cases, you use this form, which is 2ⁿ such that n is the number of items in the set. If there is 11 items in the set, then there are 211 possible subsets!
No. Square root of (2, or 3, or 5, or 6, or 7, or 8, or 10, or 11) are all real and irrational.
11
11
is 7 and 8 and 11
To any set that contains it! It belongs to {-22}, or {-22, sqrt(2), pi, -3/7}, or all whole numbers between -43 and 53, or multiples of 11, or composite numbers, or integers, or rational numbers, or real numbers, etc.
Any set of numbers that contain them! For example, they belong to the set {10, 11} or {10, 11, sqrt(2), pi, -3/7}, or {10, 11, bananas, France, cold} or all whole numbers between 3 and 53, or counting numbers, or integers, or rational numbers, or real numbers, or complex numbers, etc.
rational and prime numbers
Yes, 3.5 is real number.Real numbers include all numbers except complex numbers which are of the form a+ib where a & b are real numbers and i = -11/2
Note that an empty set is included for the set of 11 numbers. That is 1 subset. Since order doesn't matter for this type of situation, we count the following number of subsets. 1-item subset: 11 choose 1 2-item subset: 11 choose 2 3-item subset: 11 choose 3 4-item subset: 11 choose 4 5-item subset: 11 choose 5 6-item subset: 11 choose 6 7-item subset: 11 choose 7 8-item subset: 11 choose 8 9-item subset: 11 choose 9 10-item subset: 11 choose 10 11-item subset: 11 choose 11 Note that the pattern of these values follows the Fibonacci sequence. If we add all of these values and 1 altogether, then you should get 2048 subsets that belong to the given set {1,2,3,4,5,6,7,8,9,10,11}. Instead of working out with cases, you use this form, which is 2ⁿ such that n is the number of items in the set. If there is 11 items in the set, then there are 211 possible subsets!
How many subsets are there in 2 3 5 7 11 13 17 19 23?
Among the real whole numbers, you only have two choices: -1 x 11 and 1 x -11
No. Square root of (2, or 3, or 5, or 6, or 7, or 8, or 10, or 11) are all real and irrational.
11
11
is 7 and 8 and 11
The answer is 12 every other numbers are odd numbers, but 12 is an even number