3/5 (3 over 5) or 0.6 as a decimal.
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The product of 5 and t is simply written 5t. This can't be further simplified, unless you know, and replace, a value for t.The product of 5 and t is simply written 5t. This can't be further simplified, unless you know, and replace, a value for t.The product of 5 and t is simply written 5t. This can't be further simplified, unless you know, and replace, a value for t.The product of 5 and t is simply written 5t. This can't be further simplified, unless you know, and replace, a value for t.
(4t2 - 16)/8 ÷ (t - 2)/6 = [4(t2 - 4)/8] x 6/(t - 2) = (t2 - 22)/2 x 6/(t - 2) = (6/2)[(t + 2)(t - 2)/(t - 2)] = 3(t + 2) = 3t + 6
t(n) = 5 + 2*n
t = s/v s = 15 km v = 100 km/h t = 15 km/(100 km/h) = 0,15 h = 9 minutes.
r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)