In the number 42256, there are two occurrences of the digit 2. The values of these 2s are 20, which comes from the second position (tens place), and 2, which comes from the fifth position (units place). Therefore, the values of the 2s in 42256 are 20 and 2.
4: 4000, 6: 600, 7: 70, 8: 8. These are the values for each digit in 4678.
In the number 90.23, the value of the digit 9 is 90, the value of the digit 0 is 0, the value of the digit 2 is 0.2, and the value of the digit 3 is 0.03. Thus, the digit values together represent the number as a whole.
To write 15,409 in expanded form, you break it down based on the place values of each digit. It can be expressed as 10,000 + 5,000 + 400 + 0 + 9. This highlights the contribution of each digit according to its position in the number.
Read the problem, make sure that you understand all questions. Draw the diagram. Mark all given values. Write Newton's equations using given values. Resolve the values in question.
The smallest 5 digit number you can write is 10000.
4: 4000, 6: 600, 7: 70, 8: 8. These are the values for each digit in 4678.
In the number 90.23, the value of the digit 9 is 90, the value of the digit 0 is 0, the value of the digit 2 is 0.2, and the value of the digit 3 is 0.03. Thus, the digit values together represent the number as a whole.
9 is in the thousands place. 4 is in the tens place.
5
there could be a part in it like this: int num, digit; int count [10]; do { digit = num%10; num != 10; ++count[digit]; } while (num);
To write 15,409 in expanded form, you break it down based on the place values of each digit. It can be expressed as 10,000 + 5,000 + 400 + 0 + 9. This highlights the contribution of each digit according to its position in the number.
Read the problem, make sure that you understand all questions. Draw the diagram. Mark all given values. Write Newton's equations using given values. Resolve the values in question.
If you look up the ASCII values for digits, you'll see that 0 = 48, 1 = 49... 9 = 57. So it's a simple matter of adding 48 to your digit to find out the ASCII value for it.
The smallest 5 digit number you can write is 10000.
To write 5.357 in expanded form, you break it down into its place values. It can be expressed as 5 + 0.3 + 0.05 + 0.007. This shows the value of each digit based on its position in the number.
write an addition story for two 3-digit numbers. write the answer to your story
You just write a 6.