2f
f+4(f-2)
To find f(-2), substitute -2 into the function f(x). So, f(-2) = 2(-2)^3 - 2(-2)^2 + 50. Simplifying this expression gives f(-2) = 2(-8) - 2(4) + 50 = -16 - 8 + 50 = 26.
Use the remainder theorem:- f(x) = x3+nx2+3x-5 f(x) becomes f(2) because the divisor is x-2 and 2-2 = 0 f(2) = 8+4n+6-5 = -3 f(2) = 4n+9 = -3 f(2) = 4n = -12 f(2) = n = -3 So the value of n in the expression is -3 Check: f(2) = 8+(4*-3)+6-5 = -3
9
It is not possible to find the expression of 2y if f(x) = 2x - 3x.
The solubility product expression for CaF2(s) is written as Ksp = [Ca2+][F-]^2, where brackets denote the concentration of each ion at equilibrium.
14.2f
f+4(f-2)
It is 5*f where f is an expression.
Because f represents a function.
To find f(-2), substitute -2 into the function f(x). So, f(-2) = 2(-2)^3 - 2(-2)^2 + 50. Simplifying this expression gives f(-2) = 2(-8) - 2(4) + 50 = -16 - 8 + 50 = 26.
The expression for the time derivative of kinetic energy in a dynamic system is given by the equation: dKE/dt F v, where dKE/dt represents the time derivative of kinetic energy, F is the force acting on the system, and v is the velocity of the system.
Use the remainder theorem:- f(x) = x3+nx2+3x-5 f(x) becomes f(2) because the divisor is x-2 and 2-2 = 0 f(2) = 8+4n+6-5 = -3 f(2) = 4n+9 = -3 f(2) = 4n = -12 f(2) = n = -3 So the value of n in the expression is -3 Check: f(2) = 8+(4*-3)+6-5 = -3
9
It is not possible to find the expression of 2y if f(x) = 2x - 3x.
It is an expression and can be simplified to: 3d+f+1
341+f