To find the missing length of a right triangle with legs measuring 15 inches and 12 inches, you can use the Pythagorean theorem: (a^2 + b^2 = c^2), where (c) is the hypotenuse. Here, (15^2 + 12^2 = c^2) gives (225 + 144 = c^2), resulting in (c^2 = 369). Therefore, the hypotenuse (c) is ( \sqrt{369} \approx 19.2 ) inches.
No because 12+14 = 26 which is less than 28 and so therefore constructing a triangle is impossible.
1ft = 12in 1ft3 = 1ft x 1ft x 1ft = 12in x 12in x 12in = 1728in3 => 3.25ft3 = 3.25 x 1728in3 = 5616in3
1ft = 12in 131in x 1ft/12in = 10.9in
1ft = 12in 3.5ft = 3.5 x 12in = 42in
I assume you mean an 8ft x 6ft room, which is 48ft2. I assume you mean 12in x 12in tiles, which are 1ft2 tiles. I don't know how many tiles are in a box, but you would need 48 12in x 12in tiles.
No but nearly
More than one unique triangle exists with the given side lengths.
No because 12+14 = 26 which is less than 28 and so therefore constructing a triangle is impossible.
12in or 11 in all the way around say if you could make a softball flat that is how long it would be
(12in x 12in x 12in) = 1,728 in3
A square foot is 12in x 12in or 144 sq. in.
1ft = 12in 1ft3 = 1ft x 1ft x 1ft = 12in x 12in x 12in = 1728in3 => 3.25ft3 = 3.25 x 1728in3 = 5616in3
1ft = 12in 27ft x 12in/1ft = 324in
1ft = 12in 131in x 1ft/12in = 10.9in
1ft = 12in 768in x 1ft/12in = 64ft
12in = 1 foot. 60in / 12in = 5 ft
1ft = 12in 3.5ft = 3.5 x 12in = 42in