The standard form of ( 5x^4 ) is simply the expression itself, as it is already in standard form. In polynomial notation, it is written with the coefficient (5) followed by the variable (x) raised to the power of 4. If you're looking for a numerical representation or a different form, please clarify!
(1/2*-1/4)*(5x^2-2x+6) = -0.625x^2+0.25x-0.75
-5x + 729
To do this equation, there would have to be an = in it. If you mean 5x-2y=4, then: 5x-2y=4 -5x -5x = -2y=4-5x Hope this helped!
To express the equation ( y = 5x + 1 ) in standard form, we need to rearrange it into the form ( Ax + By = C ), where A, B, and C are integers. This can be done by moving ( 5x ) to the other side of the equation: ( -5x + y = 1 ). For standard form, it's conventional to have A as a positive integer, so we can multiply the entire equation by -1: ( 5x - y = -1 ). Thus, the standard form is ( 5x - y = -1 ).
4 + 5x = 1 5x = 1 - 4 5x = -3 x = -3/5 x = -0.6
Standard form is 5x - 2y = -23
25x2 + 40x + 16 = 25x2 + 20x + 20x + 16 = 5x(5x + 4) + 4(5x + 4) = (5x + 4)(5x + 4) or (5x + 4)2
(1/2*-1/4)*(5x^2-2x+6) = -0.625x^2+0.25x-0.75
-5x + 729
To do this equation, there would have to be an = in it. If you mean 5x-2y=4, then: 5x-2y=4 -5x -5x = -2y=4-5x Hope this helped!
The standard form is: 5x - y + 4 = 0
If you mean y = 5x-13 then in standard form it is 5x-y-13 = 0
To express the equation ( y = 5x + 1 ) in standard form, we need to rearrange it into the form ( Ax + By = C ), where A, B, and C are integers. This can be done by moving ( 5x ) to the other side of the equation: ( -5x + y = 1 ). For standard form, it's conventional to have A as a positive integer, so we can multiply the entire equation by -1: ( 5x - y = -1 ). Thus, the standard form is ( 5x - y = -1 ).
4 + 5x = 1 5x = 1 - 4 5x = -3 x = -3/5 x = -0.6
8x - 4 = -7 + 5x8x - 5x - 4 = -7 + 5x - 5x subtract 5x from both sides3x - 4 + 4 = -7 + 4 add 4 to both sides3x = -3x = -3/3 = -1
5x + y = 5
If -4 + 5x = 6, 5x = 6 +4 = 10 or x = 2.