3.5858 and 6.4142 approx.
-55
No, it is impossible.
The first ten positive numbers total 55.
The sum first Prime number is (2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23 + 29 ) = 129 The sum of the first composite numbers is (4 + 6 + 8 + 9 + 10 + 12 + 14 + 15 + 16 + 18) = 112 The difference is 129 - 112 = 17 !!!!!
nine, ten and eleven. Three consecutive numbers that total thirty
3.5858 and 6.4142 approx.
thousands
100
-55
1, 2 and 3.
No, it is impossible.
It is 110.
The sum is twenty three thousand,one hundred and ten
The first ten positive numbers total 55.
When the sum of the numbers is ten or greater.
The numbers are 10 and 5