3.5858 and 6.4142 approx.
-55
No, it is impossible.
The sum first Prime number is (2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23 + 29 ) = 129 The sum of the first composite numbers is (4 + 6 + 8 + 9 + 10 + 12 + 14 + 15 + 16 + 18) = 112 The difference is 129 - 112 = 17 !!!!!
The first ten positive numbers total 55.
nine, ten and eleven. Three consecutive numbers that total thirty
3.5858 and 6.4142 approx.
100
thousands
-55
1, 2 and 3.
No, it is impossible.
It is 110.
The sum is twenty three thousand,one hundred and ten
The sum first Prime number is (2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23 + 29 ) = 129 The sum of the first composite numbers is (4 + 6 + 8 + 9 + 10 + 12 + 14 + 15 + 16 + 18) = 112 The difference is 129 - 112 = 17 !!!!!
When the sum of the numbers is ten or greater.
The numbers are 10 and 5