3 x 5 x 10
3*5*10=150
Let's denote the three consecutive numbers as x, x+1, and x+2. Since the sum of these three numbers is 150, we can write the equation x + (x+1) + (x+2) = 150. Simplifying this equation gives us 3x + 3 = 150. Solving for x, we get x = 49. Therefore, the three consecutive numbers are 49, 50, and 51.
100+25+25 = 150
50 times 3 is 150
149 of them.
They can be: 2+59+89 = 150
The range of these three numbers is equal to 150 - 50 = 100
They are: 48+50+52 = 150
Three times three times three.
2, 3, and 5 are the three different prime factors of 150.
They are: 2*3*25 = 150