2,3 and 28
312
(84,2)(56,3)(42,4)(28,6)(24,7)(21,8)(14,12)
163, 3, 2
No. In order for two factors (i.e. two numbers multiplied together) to result in an even number, at least one of the factors must be even. Except for "2" all prime numbers by definition must be odd numbers. 168/2 = 84. 84 is not prime. Therefore you are looking for 2 odd factors of 168. But this is a fruitless search as 2 odd numbers multiplied together will never result in an even number.
-146
-166
These pairs of numbers when multiplied equal 168: (1, 168) (2, 84) (3, 56) (4, 42) (6, 28) (7, 24) (8, 21) (12, 14)
312
2 x 7 x 12
(84,2)(56,3)(42,4)(28,6)(24,7)(21,8)(14,12)
The numbers below are the factor pairs of 168. Multiplied together they equal 168: (1, 168) (2, 84) (3, 56) (4, 42) (6, 28) (7, 24) (8, 21) (12, 14)
163, 3, 2
Let the number be n-1, n , n+1 ( consecutive). Adding n - 1 + n + n + 1 = 504 3n = 504 n = 504/3 n = 168 n-1 = 167 n + 1 = 169 Hence the consecutive njumberscare ; - 167, 168, 169
No. In order for two factors (i.e. two numbers multiplied together) to result in an even number, at least one of the factors must be even. Except for "2" all prime numbers by definition must be odd numbers. 168/2 = 84. 84 is not prime. Therefore you are looking for 2 odd factors of 168. But this is a fruitless search as 2 odd numbers multiplied together will never result in an even number.
-146
The prime factors of 168 are 23 x 3 x 7.
2*84 3*56 4*42 6*28 7*24 8*21 12*14