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Since 2058 is an even number it is divisible by 2, so let's start there. 2058 divided by 2 = 1026. Again an even number. 1026 divided by 2 = 513, not an even number, but it ends in a 3 so lets try that 513 divided by 3 = 171. That worked so now we have 4 numbers 2 x2 x3 x171, but we can break it down even further since 171 divided by 3 = 57 which is only divisible by 1 and itself (57) So here is our factors (numbers we multiply by to get another number)
1 x 2 x 2 x 3 x 3 x 57 = 2058 I would choose as my first number 57 since it is the largest and the other 2 can be 4 (2x2) and 9 (3x3) or 2 and 18 (2x3x3) or 6 and 6 (2x3 & 2x3) your choice have fun

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Q: What three numbers multiply to get 2058?
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