Oh, what a happy little math problem we have here! To find three numbers that multiply to 315, we can think of it as finding the factors of 315. The numbers that work are 5, 7, and 9. They come together beautifully to create 315, just like how different colors blend on our canvas to create a masterpiece.
The products of 315 are the numbers that can be multiplied together to equal 315. The prime factorization of 315 is 3 × 3 × 5 × 7, or (3^2 \times 5 \times 7). The factors of 315 include 1, 3, 5, 7, 9, 15, 21, 35, 45, 63, 105, and 315 itself. Thus, the products of 315 can be formed by multiplying these factors in various combinations.
63 & 5 21 & 15 9 & 35
(315,1)(105,3)(63,5)(45,7)(35,9)(21,15)
9 x 35 =351
315 multiplied by two is 630.
They are: 103+105+107 = 315
There are many possible answers. One quartet is -1, -1, 1, 315
63 & 5 21 & 15 9 & 35
(315,1)(105,3)(63,5)(45,7)(35,9)(21,15)
9 x 35 =351
10 multiplied by 315 is 3,150.
315 multiplied by two is 630.
15 multiplied by 21 is 315.
To find the numbers, you can start with any factor pair of the number and keep factoring the composite numbers until all factors are prime. 315 3 x 105 3 x 3 x 35 3 x 3 x 5 x 7 = 315
0.0603
The LCM of the given three numbers is 315
105, 210 and 315