1x68 2x34 4x17 ____ 68x1 34x2 17x4
1 x 682 x 344 x 17
There are no such whole numbers. The sum of three consecutive whole numbers must be a multiple of 3; as 68 is not a multiple of 3 (68 = 3 × 22 2/3) it cannot be the sum of three whole numbers.
Pairs of positive integer factors of 68 are: 1 x 68 2 x 34 4 x 17 And their reverses.
What number, let's call it A, when multiplied by 68% is equal to 15368% = 68 / 100 = 0.68A x 0.68 = 153A = 153 / 0.68A = 225
1x68 2x34 4x17 ____ 68x1 34x2 17x4
1, 68 2, 34 4, 17 8, 8.5 etc.
1 x 682 x 344 x 17
I don't understand your question but I can assume you're using whole numbers less than 68 and greater than 1 to find multiplicand pairs that equal 68. Given that, 68 breaks down into the integers 2, 2, and 17 (multiplied together they equal 68). So anyone combination of these three numbers will give you your axb=68 equations. So in this example you can have 2x34 or 4x17 besides the obvious 1*68
Two numbers that equal 136 are 136/1 and 0.007352941.
2 x 34 4 x 17
which number equals to 68%
The only number that equals 68 is 68. There aren't any others.
There are no such whole numbers. The sum of three consecutive whole numbers must be a multiple of 3; as 68 is not a multiple of 3 (68 = 3 × 22 2/3) it cannot be the sum of three whole numbers.
The three numbers will have a mean of 204/3 = 68. The two numbers are therefore 66, 68, 70.
Pairs of positive integer factors of 68 are: 1 x 68 2 x 34 4 x 17 And their reverses.
What number, let's call it A, when multiplied by 68% is equal to 15368% = 68 / 100 = 0.68A x 0.68 = 153A = 153 / 0.68A = 225