Let a and b represent the numbers. ab = 185 a + b = 42 From this get b = 42 - a. Substitute into ab = 185. a(42 - a) = 185 -a2 + 42a - 185 = 0 a2 - 42a + 185 = 0 Factoring, we get (a - 5)(a - 37) = 0 Therefore the two numbers are 5 and 37.
If 5 and 37 are multiplied, the answer would be 185.
The answer is ..............180 and 5. So 180 + 5 = 185 and 180*5=900.
You need at least two numbers to find a GCF.
185 ÷ 48 = 3 remainder 41
Any of its factors
There are no two such numbers. 185 is equal to 185. No other number is equal to 185.
can urination cause diabetic numbers to go down
All multiples of 185 are divisible by it.
Let a and b represent the numbers. ab = 185 a + b = 42 From this get b = 42 - a. Substitute into ab = 185. a(42 - a) = 185 -a2 + 42a - 185 = 0 a2 - 42a + 185 = 0 Factoring, we get (a - 5)(a - 37) = 0 Therefore the two numbers are 5 and 37.
If 5 and 37 are multiplied, the answer would be 185.
185-15=170 170/2=85 85+15=100 100+85=185 So the numbers are 100 and 85.
The answer is ..............180 and 5. So 180 + 5 = 185 and 180*5=900.
numbers are 37 and 5
You need at least two numbers to find a GCF.
The two numbers are 180 and 5 180 + 5 = 185 180 x 5 = 900
Yes, 185 is divisible by 10 because 185 divided by 10 is 18.5 so yes it does go in.