0
-33 = -27
This is a single-equation algebra problem, and can be stated using the variable T to stand for the number of Third Grade students (our answer).The equation is Fifth Grade + Fourth Grade + Third Grade = 33 total members.In terms of T, this is (T+6) + (T) + (T) = 33Which reduces to 3T + 6 = 33 and 3T = 27 and T = 9.There are 9 third-grade students, 9 fourth-grade students, and 15 fifth-grade students = 33.
7.33 equals 7 and 33 hundredths or 7 and one third.
33 = 27 24 = 16 The first one looks bigger.
x5 = 33 1/3, solve for x. x is the fifth root of 33 1/3. If your scientific calculator doesn't have a specific key for nth. root, raise the number to the power 0.2 (that is, 1/5).
0
33.3333
(33)2.
-33 = -27
This is a single-equation algebra problem, and can be stated using the variable T to stand for the number of Third Grade students (our answer).The equation is Fifth Grade + Fourth Grade + Third Grade = 33 total members.In terms of T, this is (T+6) + (T) + (T) = 33Which reduces to 3T + 6 = 33 and 3T = 27 and T = 9.There are 9 third-grade students, 9 fourth-grade students, and 15 fifth-grade students = 33.
It Is: 62*33 = 972
7.33 equals 7 and 33 hundredths or 7 and one third.
3 to the third power is 3 X 3 X 3 =27
33 = 27
63 = (2x3)3 = 23 x 33 36 = 33+3 = 33 x 33 As 2 ≠ 3 then 23 ≠ 33 ⇒ 63 = 23 x 33 ≠ 33 x 33 = 36 ⇒ 63 ≠ 36
33 and a third percent of $10,000 is equal to $3,333.33. To calculate this, you first find one third of $10,000 by dividing $10,000 by 3, which equals $3,333.33. Therefore, 33 and a third percent of $10,000 is $3,333.33.