63.
Let the smaller factor be n-1.
Then with a difference of 2, the larger factor is (n-1) + 2 = n+1
The sum of these is:
(n-1) + (n+1) = 2n = 16 ⇒ n=8
Thus the factors are
and the number is 7x9 = 63.
(The complete list of factor pars for 63 is: 1 & 63, 3 & 21, 7 & 9.)
Alternatively, if you don't want the simultaneous equations "hidden":
Let the two factors be x & y (so that the number is xy) with x bigger than y. Then
Adding the two equations gives:
2x = 18
⇒ x = 9
and substituting in equation 1 gives:
9 + y = 16
⇒ y = 7
and substituting in equation 2 to check:
9 - 7 = 2 as required.
So the factors are 7 & 9 and so the number is xy = 7x9 = 63.
63? But it has more than two one-digit factors.
The one digit number that has the same number of factors as the number six is three. Six's factors are 1, 2, 3, and 6 while three's factors are 1 and 3. Therefore, both numbers have the same number of factors.
To find a two-digit number multiplied by a one-digit number that equals 27, we can consider the factors of 27. The two-digit number must be 27 divided by a one-digit factor. The valid combinations are 27 = 9 × 3, where 9 is a one-digit number, and 27 divided by 3 gives us 9, which is also a one-digit number. Therefore, a valid two-digit number multiplied by a one-digit number to get 27 does not exist since 27 itself is a two-digit number.
Sure. Any 1-digit number contains only one-digit numbers as factors. Any larger number, on the other hand, contains itself as a factor, so these can be excluded.
it'll definately one '1'
63? But it has more than two one-digit factors.
63
63.
The largest one digit number that has three factors is 9. Its factors are 1, 3, and 9.
The one digit number that has the same number of factors as the number six is three. Six's factors are 1, 2, 3, and 6 while three's factors are 1 and 3. Therefore, both numbers have the same number of factors.
1620 is one.
Each digit is a prime number that has only two factors which are itself and one The prime factors of the number 22 are 2 and 11
To find a two-digit number multiplied by a one-digit number that equals 27, we can consider the factors of 27. The two-digit number must be 27 divided by a one-digit factor. The valid combinations are 27 = 9 × 3, where 9 is a one-digit number, and 27 divided by 3 gives us 9, which is also a one-digit number. Therefore, a valid two-digit number multiplied by a one-digit number to get 27 does not exist since 27 itself is a two-digit number.
2530000000 is one such number.
9 has three factors: 1, 3, and 9
4 : with factors 1, 2 and 4
There are many 4 digit numbers having 3 and 11 as factors. One of them is 1089 whose factors are 3,3,11,11.