-7 and -8 is one possible pair.
There are no two consecutive primes whose sum, difference, product or quotient is 56.However, there may be some non-standard binary operation such that two primes can be combined to make 56.
14x4
4 and 14
7*8=56
It is: (77+32)*(56-45) = 1199
11, 12 -11, -12
Two.
There are no two consecutive primes whose sum, difference, product or quotient is 56.However, there may be some non-standard binary operation such that two primes can be combined to make 56.
14x4
The product of 8 & 7 is 56 (8x7=56)
Objective 56: Reach a Breeder's Reserve That Ends With 77. All you have to do is look at the last two digits of your equus and work until the last two digits are 77.
4 and 14
7*8=56
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
It is: (77+32)*(56-45) = 1199
-56 and -1 -56+(-1)=-57 -56*(-1)=56
2 x 56.