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-7 and -8 is one possible pair.

Q: What two digits have a difference of 1 and a product of 56?

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There are no two consecutive primes whose sum, difference, product or quotient is 56.However, there may be some non-standard binary operation such that two primes can be combined to make 56.

14x4

4 and 14

7*8=56

It is: (77+32)*(56-45) = 1199

Related questions

(+7 and +8) and (-7 and-8)

11, 12 -11, -12

Two.

There are no two consecutive primes whose sum, difference, product or quotient is 56.However, there may be some non-standard binary operation such that two primes can be combined to make 56.

14x4

Objective 56: Reach a Breeder's Reserve That Ends With 77. All you have to do is look at the last two digits of your equus and work until the last two digits are 77.

4 and 14

The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56

7*8=56

-56 and -1 -56+(-1)=-57 -56*(-1)=56

It is: (77+32)*(56-45) = 1199

2 x 56.