There are no such real numbers.
Let the numbers be x and (2-x). The equation representing the question is:
x(2-x) = 24 <=> 2x-x2 = 24 <=> 2x = x2+24 <=> 0 = x2-2x+24 <=> x2-2x+24=0.
In solving this equation, a=1, b=-2 and c=24. The discriminant is b2-4ac = (-2)2-4(1)(24) = 4-96 = -92.
Since the discriminant is negative, the equation has no solution.
34
The two numbers that add to give you 25 and multiply to give you 26 are 24 and 1. When you add 24 and 1, you get 25, and when you multiply them, you get 26.
34
-22
The two numbers that multiply to 24 and add up to -11 are -3 and -8. When multiplied, -3 × -8 equals 24, and when added, -3 + -8 equals -11.
14
20
34
11 and 13
The two numbers that add to give you 25 and multiply to give you 26 are 24 and 1. When you add 24 and 1, you get 25, and when you multiply them, you get 26.
-101
34
-22
13
26
-29
1