There are no such real numbers.
Let the numbers be x and (2-x). The equation representing the question is:
x(2-x) = 24 <=> 2x-x2 = 24 <=> 2x = x2+24 <=> 0 = x2-2x+24 <=> x2-2x+24=0.
In solving this equation, a=1, b=-2 and c=24. The discriminant is b2-4ac = (-2)2-4(1)(24) = 4-96 = -92.
Since the discriminant is negative, the equation has no solution.
34
The two numbers that add to give you 25 and multiply to give you 26 are 24 and 1. When you add 24 and 1, you get 25, and when you multiply them, you get 26.
34
-22
26
14
20
11 and 13
34
34
-101
-22
-29
26
13
1
21