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Best Answer
There are no such real numbers.
Let the numbers be x and (2-x). The equation representing the question is:
x(2-x) = 24 <=> 2x-x2 = 24 <=> 2x = x2+24 <=> 0 = x2-2x+24 <=> x2-2x+24=0.
In solving this equation, a=1, b=-2 and c=24. The discriminant is b2-4ac = (-2)2-4(1)(24) = 4-96 = -92.
Since the discriminant is negative, the equation has no solution.
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