a+b=6, or a=6-b
a*b=1
substitute for a in the 2nd equation, using the first equation:
(6-b)*b=1
-b2+6b-1=0
b2-6b+1=0
Using the quadratic equation,
b = (6 +- (36-4).5)/2 = 3 +- 2(2).5
a = 6 - (3 +- 2(2).5) = 3 +- 2(2).5
(a,b) = (3+2(2).5,3-2(2).5) or (3-2(2).5,3+2(2).5)
-21, 27
3 and 2 3 x 2 = 6 3 + 2 = 5
Product = multiply.
341
There are no two consecutive numbers that add or multiply to 102.
Ten and six.
3x-3
-10 and 4,
111
-21, 27
You add six to two and you will get 8. If you wanted it six times more than two, you have to multiply the two numbers. You will get 12.
To solve this problem, we are looking for two numbers that multiply to 150 and add to -19. Letβs break it down: Product of the two numbers: The two numbers should multiply to give 150. Sum of the two numbers: The same two numbers should add up to -19.
There are no two real numbers that do, but the complex numbers (2 + i) and (2 - i) will.If you want two numbers that multiply to negative 5 and add to positive 4 then: -1 and 5If you want two numbers that multiply to negative 5 and add to negative 4 then: 1 and -5
3 and 2 3 x 2 = 6 3 + 2 = 5
The two numbers that multiply to -72 and add to -29 are approximately 3.57 and -32.57.
14
The two numbers are -2 and -15