We can solve this by setting up two different equations.
x=1st number
y=2nd number
xy = 40
x-y = 3
We then use substitution.
x = 3+y
(y+3)y = 40
y^2 +3y = 40
y^2 +3y - 40 = 0
(y+8)(y-5) = 0
y = -8, 5
We then plug in the values for y.
x -(-8) = 3 x - 5 = 3
x=-5, 8
The two numbers could either be (-8,-5) or (5,8).
What two numbers have a difference of three a d a product of 40
I think you mean product... 4 and 9
54
5 and 8-5 and -8
391
What two numbers have a difference of three a d a product of 40
8 5
I think you mean product... 4 and 9
54
5 and 8-5 and -8
If the product of the two numbers is the sum times 24, then the product of the two numbers is 2400. 40 times 60 is 2400, and 40 plus 60 is 100. The two numbers are 40 and 60.
391
The numbers are 25 and 15
The numbers are 25 and 15
One option is 110 and 70.
10 + 4 = 14 10 x 4 = 40 10 - 4 = 6 or 4 - 10 = -6 so your answer is 6 or -6
15 and 25