2 and 57
2 x 57 = 114 3 x 38 = 114 4 x 28.5 = 114 5 x 22.8 = 114 6 x 19 = 114 8 x 14.25 = 114 10 x 11.4 = 114
The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.
Inclusively there are 114 whole numbers in this range.146 - 33 + 1 = 114.
Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.
2 and 57
The two perfect squares nearest to 114 are 100 (102) and 121 (112). Consequenly, the two whole numbers (integers) closest to √114 are 10 and 11. Note that √114 ≈ 10.677 (3dp)
1 * 114 2 * 57 3 * 38 6 * 19
The numbers are 56 and 58.
114% to make anything a percent, you move the decimal point to the right two places.
2 x 57 = 114 3 x 38 = 114 4 x 28.5 = 114 5 x 22.8 = 114 6 x 19 = 114 8 x 14.25 = 114 10 x 11.4 = 114
The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.
1 x 114, 2 x 57, 3 x 38, 6 x 19.
There are no prime numbers between 114 and 126.
6, 38, 57, 114 are the composite factors of 114.
100 + 14 = 114
19 x 6, 57 x 2, 38 x 3, or don't forget about 114 x 1.