x + y = 3, y = -x + 3
xy = 152
x(-x + 3) = 152
-x2 + 3x = 152
x2 - 3x = -152 form the square
x2 - 3x + (3/2)2 = (3/2)2 - 152
(x - 3/2)2 = 9/4 - 152
x - 3/2 = ±√[(9 - 152*4)/4]
x = 3/2 ± (√-599)/2
x = (3 ± i√599)/2
x = (3 + i√599)/2 or x = (3 - i√599)/2
y = 3 - x
y = 3 - (3 + i√599)/2
y = (6 - 3 - i√599)/2
y = (3 - i√599)/2 or y = (3 + i√599)/2
Check:
[(3 + i√599)/2][(3 - i√599)/2] = [32 - (i√599)2]/4 = (9 - 599i2)/4 =( 9 + 599)/4 = 608/4 = 152
(3 + i√599)/2 + (3 - i√599)/2 = (3 + i√599 + 3 - i√599)/2 = 6/2 = 3
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It is not possible to multiply two prime numbers and get 90. You can add 43 and 47.
Their sum is -12
they are called square numbers because, the numbers that are being multiplied by itself(5x5=25)would equal its' sum OR answer. These numbers would be a perfect square.
The sum of two numbers is those two numbers multiplied together. For instance, the sum of 4 and 5 is 20.
Not unless at least one of the numbers is zero.