There are multiple pairs of numbers that will multiply to make 294.
1,294 2,147 3,98 6,49 7,42 14,21
To get 294, you can multiply the numbers 2, 3, 7, and 7 together: (2 \times 3 \times 7 \times 7 = 294). Another combination could be 1, 2, 3, and 49, since (1 \times 2 \times 3 \times 49 = 294). Various combinations exist, but these two are valid examples.
The two numbers that add to 7 and multiply to 294 are 14 and -7. This is because 14 + (-7) = 7 and 14 * (-7) = -98, which does not satisfy the multiplication requirement. However, the correct approach involves solving the equations formed by these conditions, leading us to the correct pairs. The actual numbers that meet both conditions are 14 and -7.
The two numbers that multiply to make 40 and add to make -13 are -8 and -5. When you multiply -8 and -5, you get 40, and when you add them together, you get -13.
9
There are no two real numbers that do, but two complex numbers do: (3.5 + i 3.5 √23) and (3.5 - i 3.5 √23) If you want them to add to 7 and multiply to -294, then the two real numbers -14 and 21 work. Or if you want them to add to -7 and multiply to -294, then the two real numbers 14 and -21 work. To add to -7 and multiply to 294, the following two complex numbers work: (-3.5 + i 3.5 √23) and (-3.5 - i 3.5 √23)
301
1,294 2,147 3,98 6,49 7,42 14,21
301
To get 294, you can multiply the numbers 2, 3, 7, and 7 together: (2 \times 3 \times 7 \times 7 = 294). Another combination could be 1, 2, 3, and 49, since (1 \times 2 \times 3 \times 49 = 294). Various combinations exist, but these two are valid examples.
5 and -3
6x7
x +y = 7 xy = -294 y = 7-x x(7-x) = -294 7x - x2 +294 = 0 x2 - 7x -294 = 0 (x-21)(X+14) = 0 x = 21 Y = -14
9
Prime decomposition of 294: 294 = 2 x 3 x 7^2 Other ways of writing 294: 294 = 1 x 294 294 = 2 x 147 294 = 3 x 98 294 = 6 x 49 294 = 7 x 42 294 = 14 x 21
i have no idea what it is but i think its something you multiply by itself and you will get the answer.
When you multiply two numbers, you get the product