As a product of its prime factors: 2*2*2*2 = 16 and so there are four of them and not two of them
The two 2-digit numbers that multiply to make 176 are 11 and 16. When you multiply 11 by 16, you get 176 (11 × 16 = 176). These are the only two-digit integers that satisfy this condition.
The two numbers that multiply to 48 and add to negative 16 are -12 and -4. This is because -12 × -4 = 48 and -12 + (-4) = -16.
There are no such numbers.
16 x 61
How about: 13+3 = 16
16 and 15
The two 2-digit numbers that multiply to make 176 are 11 and 16. When you multiply 11 by 16, you get 176 (11 × 16 = 176). These are the only two-digit integers that satisfy this condition.
The two numbers that multiply to 48 and add to negative 16 are -12 and -4. This is because -12 × -4 = 48 and -12 + (-4) = -16.
There are no such numbers.
They are: 9 and 16
47
16 x 61
That's a false statement. Both 16 and 64 have one prime factor. 16 can't be the LCM of two prime numbers and 64 can't be the product. If you leave out the word prime, you can use 16 and 4.
How about: 13+3 = 16
15 and 16. or -16 and -15
-137
No. Not even close. Examples: 4+4=8 8+8=16 16+16=32 . . .4, 8, and 16 are not prime numbers.