To determine if the ratio of length to width for two rectangles is proportional, you need to compare the ratios of their lengths to widths. If the ratios are equal, then the rectangles are proportional. For example, if Rectangle A has a length of 10 units and a width of 5 units (ratio of 10:5 or 2:1), and Rectangle B has a length of 20 units and a width of 10 units (ratio of 20:10 or 2:1), then the rectangles are proportional because the ratios are equal.
You cannot.
There are no units given for the multiplications; are they:The same unitsThe multiplications could be the areas of rectangles which means the results will be SQUARE unitswhich means if the difference required is in feet and NOT SQUARE feet, is it the difference in perimeter of the two rectangles?I think you need to re-ask your question with proper units included, then we can possibly answer it.
Yes, I could draw three rectangles with 12 units, so long as the perimeter of the rectangles sum up to 12. You're probably asking for integer lengths, though. A square is a special type of rectangle where all the sides are the same length, so I could have 3 squares with a side length of 1 unit, which gives 3x(1x4)=12 units.
Length is the distance - in given units - between two points on a line.
To determine if the ratio of length to width for two rectangles is proportional, you need to compare the ratios of their lengths to widths. If the ratios are equal, then the rectangles are proportional. For example, if Rectangle A has a length of 10 units and a width of 5 units (ratio of 10:5 or 2:1), and Rectangle B has a length of 20 units and a width of 10 units (ratio of 20:10 or 2:1), then the rectangles are proportional because the ratios are equal.
Area of a rectangle in square units = length*width
You cannot.
There are no units given for the multiplications; are they:The same unitsThe multiplications could be the areas of rectangles which means the results will be SQUARE unitswhich means if the difference required is in feet and NOT SQUARE feet, is it the difference in perimeter of the two rectangles?I think you need to re-ask your question with proper units included, then we can possibly answer it.
Yes, I could draw three rectangles with 12 units, so long as the perimeter of the rectangles sum up to 12. You're probably asking for integer lengths, though. A square is a special type of rectangle where all the sides are the same length, so I could have 3 squares with a side length of 1 unit, which gives 3x(1x4)=12 units.
Rectangles have two dimensions: length and width. Multiply them together and you will get the area in square units.
Length is the distance - in given units - between two points on a line.
The length of the side of a square of area x square units is sqrt(x) units.
Perimeter = 2 x (width + length)⇒ 12 = 2 x (width + length)⇒ width + length = 6⇒ the rectangles could be:1 by 52 by 43 by 3[A square is a rectangle with equal sides.]
The answer will depend on what 640 is meant to measure: area, perimeter, length of diagonal. Who knows? Especially when no units are given. It is, therefore, impossible to give a sensible answer to this question.
All squares are rectangles (though the condition is not true vice-versa). Consider a square of side 'a' units and a rectangle of length 'l' units and breadth 'b' units. The area of the rectangle is given by lxb. Now, since all rectangles are squares, we can apply the same formula for the square. Therefore, area of the square = lxb. But, 'l' and 'b' is the same as 'a'. This implies, area of the square = axa = a^2 (a square).
Given the length of the diagonal of the square ... call it 'D units'. The area of the square is (1/2 D2) (same units)2.