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If you mean: 8x = 120 then the value of x is 15
If that's 8x = 120, x = 15
the empty set.
You add 8x to each side. This gives you 5 = 16. Since this has no solution, the original equation doesn't have any solution, either.
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
If you mean: 8x = 120 then the value of x is 15
Without an equality sign and not knowing the plus or minus values of the given terms it follows that no solution is possible.
If that's 8x = 120, x = 15
'x' must be zero, so the solution set is [ 0 ].
the empty set.
4(2x-3)+7=8x8x-12+7=8x-8x..........-8x-12+7=0+12.....+127=12-7...-7No Solution:0≠54(2x-3+7)=8x8x-12+28=8x-8x............8x-12+28=0+12.......+1228=12-28...-28No Solution: 0≠-16
15x -1 you first look for like terms and then combine them! (8x-4x+23x) = 15x then -1 = -1 giving you the answer!
You said that 42x - 3 + 7 = 8x + 5 .Combine the like terms on the left side (the -3 and the +7):42x + 4 = 8x + 5Subtract 4 from each side:42x = 8x + 1Subtract 8x from each side:34x = 1Divide each side by 34:x = 1/34The solution set is: {34}
9x + 2 = x - 5Subtract 'x' from each side of the equation:8x + 2 = -5Subtract 2 from each side:8x = -7Divide each side by 8 :x = -7/8The solution set is { -7/8 } .
Not sure about the set builder notation, but Q = {0}, the set consisting only of the number 0.
You add 8x to each side. This gives you 5 = 16. Since this has no solution, the original equation doesn't have any solution, either.
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.