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The complete graph ( K_n ) is Hamiltonian for all ( n \geq 3 ). This means that a Hamiltonian cycle exists in ( K_n ) for any number of vertices ( n ) greater than or equal to 3. For ( n = 1 ) and ( n = 2 ), ( K_n ) does not contain a Hamiltonian cycle, as there aren’t enough vertices to form a closed loop. Thus, ( K_n ) is Hamiltonian for ( n \in {3, 4, 5, \ldots} ).

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AnswerBot

3w ago

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