1000 cm3=1L
Yes. 1L=1000mL
It is -340.368 Joules.The formula is: w=-P*change in volume=-1.2atm*2.8L=-3.36L*atmThen convert the units-- 1L*atm=101.3J
1000mL = 1L 3500mL x 1L/1000mL = 3.5L So, 3L is less than 3500mL.
kg=weight L(litres)=volume so if 1L of something weighed 1KG(water=1.000028kg) then numerically L=kg so 38.8L would be(weigh) 38.8kg
To prepare a 10mM solution of Tris-HCl, you would weigh out the appropriate amount of Tris-HCl powder using a balance and dissolve it in water to make a final volume of solution. For example, to make 1L of 10mM Tris-HCl solution, you would need to dissolve 0.121g of Tris-HCl in 1L of water.
The formula weight is 121.5 --> this is equivalent to 1M with 121.5g tris in 1L dH20. For a 5M stock, use 5x as much tris in the same 1L dh20.607.5 g tris into 800ml dH2O - stirring - then pH to 7.5 with 6M HCl and QS to your final volume of 1L
1.21 g Tris-HCl, QS water to 1L. Scale appropriately.
Molarity of a solution is the number of moles of the solute divided by the volume of the solution (in liters). If 750 ml of 20M HCl is mixed with 250 ml of 60M HCl, we first find the total number of moles of HCl in our new solution. Using that same formula, M=moles/V, we cansee that moles=MV. In the first solution we have (20M)(0.750L) = 15 moles. In the second, (60M)(0.250L) = 15 moles, so we have a total of 30 moles in our new solution, which also has a volume of 750mL + 250mL = 1L. The molarity of the new solution is 30 moles/1L = 30M
50ml = .05L of HCL 1.0 M = 1mol / 1L of HCL simply multiply - .05 by 1.0, and get your answer!
1N HCl is also 1M HCl because it is mono-protic. Therefore 36.5 g of HCl is required per liter or 3.65%. Simply take 100 g of 37% HCl and make up to the 1 liter mark on the volumetric flask. Check the value by titration against 1M NaOH. It should be perfect. If very slightly strong dilute very slightly (calculate) with water and re-standardize.
1000 cm3=1L
no liter is a measurement of volume because 1L is 1000cm3 and cm3 is a measure of volume
25g / 250ml is 100g per litre. I'll let you know how to finish it. You need to divide by the molecular weight of your compound. I don't think C6H12O16 can actually exist. You may mean glucose, but that is for you to decide. It has been explained how to finish off the math in one step anyway.
They are all Metric measurements.
you use nowadays... l ml 1000ml=1l
To prepare 0.1M methanolic HCl, you would first need to calculate the volume of concentrated HCl needed to make the solution. Since methanol is the solvent, you would mix the calculated volume of concentrated HCl with methanol in a volumetric flask and dilute to the desired final volume. It is important to handle concentrated HCl with care due to its corrosive nature and always add acid to solvent, not the other way around, to avoid splattering.