21 has only two factors , 3 and 7
Both are prime numbers, divisible only by itself and 1
So the third number must be .... 1
1 x 3 x 7 = 21
( Of course this only applies, if we are talking about integers ;-) )
The three numbers that can be multiplied to get 252 are 3, 4, and 21. When you multiply these together (3 × 4 × 21), the product is 252. Other combinations are possible as well, such as 2, 6, and 21, or 2, 2, and 63.
Any number can be multiplied by 21
Any number can be multiplied to get the answer 441. For example 5 can be multiplied by 88.2 If the question was which number can be multiplied by itself, the answers are: -21 and +21
3*7 = 21
21 and 5
The three numbers that can be multiplied to get 252 are 3, 4, and 21. When you multiply these together (3 × 4 × 21), the product is 252. Other combinations are possible as well, such as 2, 6, and 21, or 2, 2, and 63.
This is no set of three consecutive numbers that when multiplied equal 387.
Any number can be multiplied by 21
Any number can be multiplied to get the answer 441. For example 5 can be multiplied by 88.2 If the question was which number can be multiplied by itself, the answers are: -21 and +21
3*7 = 21
-21
21 and 5
21
2 when multiplied by 21 = 42
10.5 x 2=21
1 x 21, 3 x 7
1x1x3150