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The acceleration of gravity is 9.8 m/s2 .

After 2.5 s, the bullet's speed is [ 172 - 2(9.8) ] = 152.4 m/s upward.

The average speed during those 2.5 seconds is [ 1/2 (172 + 152.4) ] = 162.2 m/s.

In 2.5 seconds at that average speed, the bullet travels (162.2 x 2.5) = 405.5 meters.

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Q: What will be its displacement after 2.5s when a bullet is fired straight up from a gun with a muzzle velocity of 172 meters per second and the acceleration of gravity is 9.8 meters per sec sq.?
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Related questions

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