If 18 091 997 is a series of three separate numbers the roman numerals for them would be 18 = XVIII, 091 = XCI and 997 = CMXCVII.
1003
It is 997/1000 as a decimal equals 0.997
1000* * * * *NO. That is 997 rounded to the nearest ten. A tenth is 1/10 and 997 rounded to the nearest tenth is 997 or, if you need to show the degree of accuracy, 997.0
997/1,000 no further reduction possible as 997 is a prime number
It is 997.It is 997.It is 997.It is 997.
The answer is 0. The value would have to be 5000 or higher to round up to 10000.
The answer must have an even number and an odd number, because if you add two odd numbers, the sum would be even. Therefore, the first answer is the only prime even number: 2. 2 + 997 is 999, so the other answer would be 997. 997+2 (!?!) 997+2 (!?!) 2 and 997
I would recommend against it, with both vehicles' performance specifications differing. If i can recall, a 997 S uses calipers from the Porsche 911 turbo, which is drastically different from the standard 997.
If 18 091 997 is a series of three separate numbers the roman numerals for them would be 18 = XVIII, 091 = XCI and 997 = CMXCVII.
1003
Oh, dude, 997 rounded off to the nearest hundred is 1000. Like, you just gotta look at that last digit, which is a 7, and if it's 5 or more, you round up. So, 997 becomes 1000. Easy peasy, lemon squeezy.
1, 997.
1000
I would love too ;}
997 multiplied by 72 is 71,784.
997/1000