Hi All answered in http://zone.ni.com/devzone/cda/tut/p/id/4782 = Relay Forms = 121 ratings | 4.61 out of 5 | Print DocumentRelays are classified by their number of poles and number of throws. The pole of a relay is the terminal common to every path. Each position that the pole can connect to is called a throw. A relay can be made of n poles and m throws. For example, a single-pole single-throw relay (SPST) has one pole and one throw, as illustrated in the following figure. A single-pole double-throw (SPDT) relay has one pole and two throws, as illustrated in the following figure: A double-pole double-throw (DPDT) relay has two poles, each with two simultaneously controlled throws, as illustrated in the following figure: Relays are then classified into forms. Relay forms are categorized by the number of poles and throws as well as the default position of the relay. Three common relay forms are: A, B, and C. Form A Form A relays are SPST with a default state of normally open. Form B Form B relays are SPST with a default state of normally closed. Form C Form C relays are SPDT and break the connection with one throw before making contact with the other (break-before-make).
Slope intercept form would be: y = mx + b So, you already know m=-3 so you have to figure out b. So we will substitute (1,1) for (x,y) and solve for b. 1 = (-3) (1) + b 1 = -3 + b 4 = b So, now you can write: y=-3x +4
Slope intercept form is y=mx+b the m would stand for your slope and b would stand for you y intercept written as (0,b)
The form is a*10b where 1 ≤ a < 10 and b is an integer.
It requires that the decimal is converted to the form a*10^b where 1 < a ≤ 10 and b is an integer. The standard form is also known as the scientific form.
y = 4x + 1, is in the slope-intercept form, y = mx + b, where the slope, m, is 4, and the y-intercept, b, is 1.
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There is no such thing as the highest form since, if A/B laid claim to being the highest form, then (A+1)/(B+11) is equivalent AND higher.
Rational fractions of the form a/b where both a and b are integers, b > 0 and, in its simplified form, the denominator is not 1.
Slope intercept form would be: y = mx + b So, you already know m=-3 so you have to figure out b. So we will substitute (1,1) for (x,y) and solve for b. 1 = (-3) (1) + b 1 = -3 + b 4 = b So, now you can write: y=-3x +4
These are rational number that are not integers. In their simplest form, they are of the form a/b where a and b are integers and b is not 0 nor 1.
Slope intercept form is y=mx+b the m would stand for your slope and b would stand for you y intercept written as (0,b)
a + i b, with a and b real numbers and i = sqrt(-1)
The form is a*10b where 1 ≤ a < 10 and b is an integer.
They do not. At the start, A+B = 101 is odd After every change, A+B remains odd. If there was a point where A=B then A+B would be 2A (or 2B) which would be even.
In grade form that would equate to a B, maybe a B+ to some.