Q: What would be the correct order for these numbers 2.01 2.1 2.001?

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What two numbers multiplied together equal 2001

1, 3, 23, 29, 69, 87, 667 and 2001.

2001 is the correct answer.

No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.

What numbers would you like to be the next three? It is possible to find a polynomial of order 5 that will fit these three numbers and ANY other three numbers. For example, using the positin to value rule given by Un= -112.275n5 + 1,966.25n4 - 12,744.625n3 + 37,416.25n2 - 48,979.6 + 36,525 I can fit the numbers 1, 2 and 3 as the next three. So there are infinitely many possible answers to the question. Using the simplest rule, although the question does not require that, gives Un = 70n + 2001 and that requires the next three numbers to be 2281, 2351, 2421.

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