The slope of the line joining (0,3) and (3,0) is -1
this would be a slope of 5
The slope of that would be 0.75 - if you follow the the equation; y2 - y1 x2 - x1
Points: (-4, 0) and (3, -3) Slope: -3/7
The slope is undefined.
If you mean points of (0, -3) and (-6, 7) then the slope is -5/3
this would be a slope of 5
The slope of that would be 0.75 - if you follow the the equation; y2 - y1 x2 - x1
The slope is undefined.
The slope would be 3/4
Slope: (2-4)/(0--3) = -2/3 Perpendicular slope: 3/2
The slope equation is y = mx + b where m is slope for y = 3 we have y = 0 (x) +3 so m = 0 = slope So slope is zero line is constant y = 3
Equation: y--3 = -3(x-0) => y = -3x-3
The slope is zero.
Points: (-2, -3) and (4, 0) Slope: (-3-0)/(-2-4) = 1/2
Slope = 7--3 over 0-8 = -5/4
There is no slope because it works out as 0
the slope is 0