A number with 17 zeros is called a "hundred quadrillion." In numerical form, it is represented as 100,000,000,000,000,000. This term is part of the short scale numbering system commonly used in the United States and modern English-speaking countries.
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1.7 million = 1 700 000 Which has 5 zeros
170,000,000,000,000,000,000,000,000(17 and 25 zeros)
Oh, dude, that's a big number you got there! So, like, when you multiply 170 billion by 100 billion, you get 17 with 22 zeros after it. That's like a whole lot of zeros, man. Like, good luck fitting that number on a calculator screen!
To determine the number of trailing zeros in 85 factorial (85!), you count how many times 5 is a factor in the numbers from 1 to 85, as there are always more factors of 2 than 5. This is calculated using the formula: [ \text{Number of trailing zeros} = \left\lfloor \frac{85}{5} \right\rfloor + \left\lfloor \frac{85}{25} \right\rfloor = 17 + 3 = 20. ] Thus, 85! has 20 trailing zeros.
The lowest possible number? Or just a number? A easy method would be to just multiply 17 & 19 17 X 19 = 323