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Mean: 67.143

Median: 78

Mode: 56, 78, 85, 92, 65, 79, 15

Range: 77

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Q: What would you choose mean median mode or range for the numbers 56 78 85 92 65 79 15?

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There would be no median.

mean = 19.833... median = 19.5 mode = 19

You take those numbers and find the median number of those say you got 6 and 8, The median would be 7. If the two numbers were 6 and 6, The median would be 6. If the two numbers are 6 and 7, the median would be 6.5

You would add the two numbers in the middle and divide them by two and the answer would be the median.

Assuming that you want to discount luck (if not, the answer would be 1), and that the guesser always guesses the median of the remaining range, the answer would be the (ceiling of the log(base 2) of the count of numbers in the range). If the log(base 2) is an exact integer, add 1. Example 1, pick a number between 1 and 9. There are 9 numbers in the range, so the log(base2) of 9 is ~3.16. The ceiling of that is 4. Do not add 1 for a final answer of 4. The full range is 1,2,3,4,5,6,7,8,9. The median is 5 First guess is 5. Higher - 6,7,8,9 is remaining range. 7 and 8 are the median numbers Second Guess is 8. Lower - 6,7 is the remaining range. 6 and 7 are the median numbers. Third guess is 7. Lower - 6 is the remaining range. 6 is the median number Fourth guess is 6. Correct. Example 2, pick a number between 1 and 16. There are 16 numbers in the range, so the log(base 2) of 16 is 4. The ceiling of 4 is 4. Add the 1 because the Log(base 2) is an integer, for a final answer of 5. Full range is 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16. The median numbers are 8 and 9. First Guess is 9. Lower - 1,2,3,4,5,6,7,8 is the remaining range. 4 and 5 are the median numbers Second Guess is 4. Higher - 5,6,7,8 is the remaining range. 6 and 7 are the median numbers. Third Guess is 6. Higher - 7,8 is the remaining range. 7 and 8 are the median numbers. Fourth Guess is 7. Higher - 8 is the remaining range. 8 is the median. Fifth guess is 8. Correct Both of these examples show worst case scenarios. A "lucky guess" will reduce the number of guess needed, possibly all the way to 1. Note: I do realize that to a math purist, in the examples where I said that the median numbers were x and y, the correct answer is that the median number is between x and y. Since I can not guess the number between the two numbers, I am bending the definition of median to treat the two bordering numbers as the median when the strict definition would list the median as being between those two numbers.

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There would be no median.

mean = 19.833... median = 19.5 mode = 19

If you have numbers like 1,2,3,4,5 and 6 the median would be between 3 and 4 so the median would be 3.5

You take those numbers and find the median number of those say you got 6 and 8, The median would be 7. If the two numbers were 6 and 6, The median would be 6. If the two numbers are 6 and 7, the median would be 6.5

You would add the two numbers in the middle and divide them by two and the answer would be the median.

Use the Excel MEDIAN function. The Median is the number in the middle of a set of numbers. Half of the numbers have values greater than the median, and half have values are less. If there is an even number of numbers in the set, then MEDIAN calculates the average of the two numbers in the middle.Examples:MEDIAN of the set of numbers (1, 2, 3, 4, 5) is 3MEDIAN of the set of numbers (1, 2, 3, 4, 5, 6) is 3.5 (average of 3 and 4)

Assuming that you want to discount luck (if not, the answer would be 1), and that the guesser always guesses the median of the remaining range, the answer would be the (ceiling of the log(base 2) of the count of numbers in the range). If the log(base 2) is an exact integer, add 1. Example 1, pick a number between 1 and 9. There are 9 numbers in the range, so the log(base2) of 9 is ~3.16. The ceiling of that is 4. Do not add 1 for a final answer of 4. The full range is 1,2,3,4,5,6,7,8,9. The median is 5 First guess is 5. Higher - 6,7,8,9 is remaining range. 7 and 8 are the median numbers Second Guess is 8. Lower - 6,7 is the remaining range. 6 and 7 are the median numbers. Third guess is 7. Lower - 6 is the remaining range. 6 is the median number Fourth guess is 6. Correct. Example 2, pick a number between 1 and 16. There are 16 numbers in the range, so the log(base 2) of 16 is 4. The ceiling of 4 is 4. Add the 1 because the Log(base 2) is an integer, for a final answer of 5. Full range is 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16. The median numbers are 8 and 9. First Guess is 9. Lower - 1,2,3,4,5,6,7,8 is the remaining range. 4 and 5 are the median numbers Second Guess is 4. Higher - 5,6,7,8 is the remaining range. 6 and 7 are the median numbers. Third Guess is 6. Higher - 7,8 is the remaining range. 7 and 8 are the median numbers. Fourth Guess is 7. Higher - 8 is the remaining range. 8 is the median. Fifth guess is 8. Correct Both of these examples show worst case scenarios. A "lucky guess" will reduce the number of guess needed, possibly all the way to 1. Note: I do realize that to a math purist, in the examples where I said that the median numbers were x and y, the correct answer is that the median number is between x and y. Since I can not guess the number between the two numbers, I am bending the definition of median to treat the two bordering numbers as the median when the strict definition would list the median as being between those two numbers.

The median of that would be any of the two numbers that are the same.

No. If you mean the numbers 1, 2, 3, 4: you need to choose the number in the middle. Since in this case there are two numbers in the middle, you need to take the AVERAGE of those two numbers, not their sum.

In ord they would be 2,3,4,5,6,6,9. The mean is all of the numbers added up and divided by how many numbers there are. So it would be 2+3+4+5+6+6+9 divided by 7. So the mean is 5. The median is the number in the middle so the median is 5. If the median is 2 numbers it is the number in between those numbers. The mode is the number that is occurring the most. If there is no mode put a 0 with a slash through it which means no answer. The mode is 6 because it occurs twice and no other number does that or more. The range is the difference (subtraction) between the biggest number and the smallest number. The biggest number is 9 and the smallest number is 2. So the range would be 9-2 which is 7. Mean=5 median=5 mode=6 range= 7

another word for median would be middle because median is the middle of a set of numbers.

There is no single answer to that. You could come up with many sets of numbers that would have those properties.

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