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What would be the mean median mode and range be for this set of numbers 19 22 21 20 19 and 18?
mean = 19.833... median = 19.5 mode = 19
What happens if you have 2 Median?
You take those numbers and find the median number of those say you got 6 and 8, The median would be 7. If the two numbers were 6 and 6, The median would be 6. If the two numbers are 6 and 7, the median would be 6.5
How do find the median with 4 different numbers?
There would be no median.
How do find the median of four numbers that are not the same?
You would add the two numbers in the middle and divide them by two and the answer would be the median.
What is the minimum number of guesses needed to find a specific number if you are given the hint higher or lower for each guess you make?
Assuming that you want to discount luck (if not, the answer would be 1), and that the guesser always guesses the median of the remaining range, the answer would be the (ceiling of the log(base 2) of the count of numbers in the range). If the log(base 2) is an exact integer, add 1. Example 1, pick a number between 1 and 9. There are 9 numbers in the range, so the log(base2) of 9 is ~3.16. The ceiling of that is 4. Do not add 1 for a final answer of 4. The full range is 1,2,3,4,5,6,7,8,9. The median is 5 First guess is 5. Higher - 6,7,8,9 is remaining range. 7 and 8 are the median numbers Second Guess is 8. Lower - 6,7 is the remaining range. 6 and 7 are the median numbers. Third guess is 7. Lower - 6 is the remaining range. 6 is the median number Fourth guess is 6. Correct. Example 2, pick a number between 1 and 16. There are 16 numbers in the range, so the log(base 2) of 16 is 4. The ceiling of 4 is 4. Add the 1 because the Log(base 2) is an integer, for a final answer of 5. Full range is 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16. The median numbers are 8 and 9. First Guess is 9. Lower - 1,2,3,4,5,6,7,8 is the remaining range. 4 and 5 are the median numbers Second Guess is 4. Higher - 5,6,7,8 is the remaining range. 6 and 7 are the median numbers. Third Guess is 6. Higher - 7,8 is the remaining range. 7 and 8 are the median numbers. Fourth Guess is 7. Higher - 8 is the remaining range. 8 is the median. Fifth guess is 8. Correct Both of these examples show worst case scenarios. A "lucky guess" will reduce the number of guess needed, possibly all the way to 1. Note: I do realize that to a math purist, in the examples where I said that the median numbers were x and y, the correct answer is that the median number is between x and y. Since I can not guess the number between the two numbers, I am bending the definition of median to treat the two bordering numbers as the median when the strict definition would list the median as being between those two numbers.
What would be the mean median mode and range be for this set of numbers 19 22 21 20 19 and 18?
mean = 19.833... median = 19.5 mode = 19
What is the median if there is an even amount of numbers?
If you have numbers like 1,2,3,4,5 and 6 the median would be between 3 and 4 so the median would be 3.5
What happens if you have 2 Median?
You take those numbers and find the median number of those say you got 6 and 8, The median would be 7. If the two numbers were 6 and 6, The median would be 6. If the two numbers are 6 and 7, the median would be 6.5
How do find the median with 4 different numbers?
There would be no median.
How do find the median of four numbers that are not the same?
You would add the two numbers in the middle and divide them by two and the answer would be the median.
What is the minimum number of guesses needed to find a specific number if you are given the hint higher or lower for each guess you make?
Assuming that you want to discount luck (if not, the answer would be 1), and that the guesser always guesses the median of the remaining range, the answer would be the (ceiling of the log(base 2) of the count of numbers in the range). If the log(base 2) is an exact integer, add 1. Example 1, pick a number between 1 and 9. There are 9 numbers in the range, so the log(base2) of 9 is ~3.16. The ceiling of that is 4. Do not add 1 for a final answer of 4. The full range is 1,2,3,4,5,6,7,8,9. The median is 5 First guess is 5. Higher - 6,7,8,9 is remaining range. 7 and 8 are the median numbers Second Guess is 8. Lower - 6,7 is the remaining range. 6 and 7 are the median numbers. Third guess is 7. Lower - 6 is the remaining range. 6 is the median number Fourth guess is 6. Correct. Example 2, pick a number between 1 and 16. There are 16 numbers in the range, so the log(base 2) of 16 is 4. The ceiling of 4 is 4. Add the 1 because the Log(base 2) is an integer, for a final answer of 5. Full range is 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16. The median numbers are 8 and 9. First Guess is 9. Lower - 1,2,3,4,5,6,7,8 is the remaining range. 4 and 5 are the median numbers Second Guess is 4. Higher - 5,6,7,8 is the remaining range. 6 and 7 are the median numbers. Third Guess is 6. Higher - 7,8 is the remaining range. 7 and 8 are the median numbers. Fourth Guess is 7. Higher - 8 is the remaining range. 8 is the median. Fifth guess is 8. Correct Both of these examples show worst case scenarios. A "lucky guess" will reduce the number of guess needed, possibly all the way to 1. Note: I do realize that to a math purist, in the examples where I said that the median numbers were x and y, the correct answer is that the median number is between x and y. Since I can not guess the number between the two numbers, I am bending the definition of median to treat the two bordering numbers as the median when the strict definition would list the median as being between those two numbers.
Would The median of 1234 be 5.?
No. If you mean the numbers 1, 2, 3, 4: you need to choose the number in the middle. Since in this case there are two numbers in the middle, you need to take the AVERAGE of those two numbers, not their sum.
What is the mean median mode and range of the numbers 6924365?
In ord they would be 2,3,4,5,6,6,9. The mean is all of the numbers added up and divided by how many numbers there are. So it would be 2+3+4+5+6+6+9 divided by 7. So the mean is 5. The median is the number in the middle so the median is 5. If the median is 2 numbers it is the number in between those numbers. The mode is the number that is occurring the most. If there is no mode put a 0 with a slash through it which means no answer. The mode is 6 because it occurs twice and no other number does that or more. The range is the difference (subtraction) between the biggest number and the smallest number. The biggest number is 9 and the smallest number is 2. So the range would be 9-2 which is 7. Mean=5 median=5 mode=6 range= 7
How do you find the median of 3 numbers with 2 of those numbers being the same?
The median of that would be any of the two numbers that are the same.
What is a synonym for median?
another word for median would be middle because median is the middle of a set of numbers.
What group of numbers has a mean of 10 median of 12 mode of 12 and a range of 12?
There is no single answer to that. You could come up with many sets of numbers that would have those properties.
Can you have a median of 0?
If you have a list of positive and negative numbers then it is possible that the median would be 0.
